mihaispr
Administrator
 Inregistrat: acum 17 ani
Postari: 2142
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//Pb1. Calculati (pow(x,4)+4*x-3)/4
#include<stdio.h>
#include<conio.h>
#include<math.h>
float x,e;
void main(void)
{clrscr();
printf("x=" );
scanf("%f",&x);
e= (float)(pow(x,4)+4*x-3)/2;
printf("E=%f",e);
getch();
}
//Pb2. Calculati expresia sqrt(a+6) pt a<0 si (pow(a,3)-2)/(a-3) pt a>=0
#include<stdio.h>
#include<conio.h>
#include<math.h>
int a;
float e;
void main(void)
{clrscr();
printf("a=" );
scanf("%d",&a);
if (a<0)
if (a>=-6)
{e=sqrt(a+6);
printf("E=%f",e);
}
else printf("Expresia nu are solutii" );
else if (a!=3)
{e= (float)(pow(a,3)-2)/(a-3);
printf("E=%f",e);
}
else printf("Expresia nu exista" );
getch();
}
//Pb3. Calculati expres. sina-cosa pt a>0;12 pt a=0 si pow(a,2)-3*a+2 pt a<0//
#include<stdio.h>
#include<conio.h>
#include<math.h>
int a;
float e;
void main(void)
{clrscr();
printf("a=" );
scanf("%d",&a);
if (a>0)
{e=sin(a)-cos(a);
printf("E=%f",e);
}
else if(a==0)
{e=12;
printf("E=%f",e);
}
else if (a<0)
{e=pow(a,2)-3*a+2;
printf("E=%f",e);
}
getch();
}
//Pb4. Calculati [2*(a+b)-(ab-bc)]/pow(a,2)-pow(b,2)
#include<stdio.h>
#include<conio.h>
#include<math.h>
int a,b,c;
float f;
void main(void)
{clrscr();
printf("a=" );scanf("%d",&a);
printf("b=" );scanf("%d",&b);
printf("c=" );scanf("%d",&c);
f= (2*a+2*b)-(a*b-b*c)/pow(a,2)-pow(b,2);
printf("Fractia=%f",f);
getch();
}
//Pb5. Calculeaza urmatorul raport (2*(a+1))-(3*b-4)/(16*a-16*b)
#include<stdio.h>
#include<conio.h>
#include<math.h>
int a,b;
float f;
void main(void)
{clrscr();
printf("a=" );scanf("%d",&a);
printf("b=" );scanf("%d",&b);
f= (2*(a+1))-(3*b-4)/(16*a-16*b);
printf("Fractia=%f",f);
getch();
}
//Pb6. Calculati x+1 pt.x<=4 si 2*x-1 pt.x>4
#include<stdio.h>
#include<conio.h>
#include<math.h>
int x;
float e;
void main(void)
{clrscr();
printf("x=" );scanf("%d",&x);
if (x<=4)
{e=x+1;
printf("Exp=%f",e);
}
else
{e=2*x-1;
printf("Exp=%f",e);
}
getch();
}
/*Pb7. De alcătuit un program ce calculează valoarea lui a şi b.
unde a=[2*co(x-pi/6)]/0.5+siny] si
b=1+ z/(3+z/5)
*/
#include<math.h>
#include<conio.h>
#include<stdio.h>
main()
{
float x,y,a,b,z,pi=3.14;
printf("introduceti x,y,z:\n" );
scanf("%f%f%f",&x,&y,&z);
a=2*cos(x-pi/6)/(1/2+pow(sin(y),2));
b= (1+pow(z,2))/(3+pow(z,2)/5);
printf("a=%f,b=%f",a,b);
getch();
}
/*Pb.8 Alcatuiti programul ce calculeaza sistemul de ecuatii:
y= a*t*ln(t) pt. 1<t<2
1 pt. t<1
e*cosb*t pt. t<2
*/
#include<conio.h>
#include<stdio.h>
#include<math.h>
main()
{
float a,b,t,y;
clrscr();
printf("introduceti variabilele" );
scanf("%f%f%f",&a,&b,&t);
if(t>=1&&t<=2) y=a*pow(t,2)+log(t);
else
if(t<1) y=1;
else
y=exp(a*t)*cos(b*t);
printf("%f",y);
}
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